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# buttord() - Signal Processing

### Syntax

### Example

### Output / Return Value

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buttord calculates the minimum order of a digital or analog Butterworth filter required to meet a set of filter design specifications.Digital Domain[n,Wn] = buttord(Wp,Ws,Rp,Rs) returns the lowest order, n, of the digital Butterworth filter with no more than Rp dB of passband ripple and at least Rs dB of attenuation in the stopband. The scalar (or vector) of corresponding cutoff frequencies, Wn, is also returned. Use the output arguments n and Wn in butter.Choose the input arguments to specify the stopband and passband according to the following table.Description of Stopband and Passband Filter ParametersParameterDescription WpPassband corner frequency Wp, the cutoff frequency, is a scalar or a two-element vector with values between 0 and 1, with 1 corresponding to the normalized Nyquist frequency, π radians per sample. WsStopband corner frequency Ws, is a scalar or a two-element vector with values between 0 and 1, with 1 corresponding to the normalized Nyquist frequency. RpPassband ripple in decibels. RsStopband attenuation in decibels. This value is the number of decibels the stopband is down from the passband. Use the following guide to specify filters of different types.Filter Type Stopband and Passband SpecificationsFilter TypeStopband and Passband ConditionsStopbandPassband LowpassWp < Ws, both scalars(Ws,1)(0,Wp) HighpassWp > Ws, both scalars(0,Ws)(Wp,1) BandpassThe interval specified by Ws contains the one specified by Wp (Ws(1) < Wp(1) < Wp(2) < Ws(2)).(0,Ws(1)) and (Ws(2),1)(Wp(1),Wp(2)) BandstopThe interval specified by Wp contains the one specified by Ws (Wp(1) < Ws(1) < Ws(2) < Wp(2)).(Ws(1),Ws(2))(0,Wp(1)) and (Wp(2),1) If your filter specifications call for a bandpass or bandstop filter with unequal ripple in each of the passbands or stopbands, design separate lowpass and highpass filters according to the specifications in this table, and cascade the two filters together.Analog Domain[n,Wn] = buttord(Wp,Ws,Rp,Rs,'s') finds the minimum order n and cutoff frequencies Wn for an analog Butterworth filter. You specify the frequencies Wp and Ws similar those described in the Description of Stopband and Passband Filter Parameters table above, only in this case you specify the frequency in radians per second, and the passband or the stopband can be infinite.Use buttord for lowpass, highpass, bandpass, and bandstop filters as described in the Filter Type Stopband and Passband Specifications table above.

[n,Wn] = buttord(Wp,Ws,Rp,Rs) [n,Wn] = buttord(Wp,Ws,Rp,Rs,'s')

Lowpass Butterworth FilterOpen This Example For data sampled at 1000 Hz, design a lowpass filter with no more than 3 dB of ripple in a passband from 0 to 40 Hz, and at least 60 dB of attenuation in the stopband. Find the filter order and cutoff frequency. Wp = 40/500; Ws = 150/500; [n,Wn] = buttord(Wp,Ws,3,60) n = 5 Wn = 0.0810 Specify the filter in terms of second-order sections and plot the frequency response.[z,p,k] = butter(n,Wn); sos = zp2sos(z,p,k); freqz(sos,512,1000) title(sprintf('n = %d Butterworth Lowpass Filter',n)) Bandpass Butterworth FilterOpen This Example Design a bandpass filter with a passband from 60 to 200 Hz with at most 3 dB of passband ripple and at least 40 dB attenuation in the stopbands. Specify a sampling rate of 1 kHz. Have the stopbands be 50 Hz wide on both sides of the passband. Find the filter order and cutoff frequencies. Wp = [60 200]/500; Ws = [50 250]/500; Rp = 3; Rs = 40; [n,Wn] = buttord(Wp,Ws,Rp,Rs) n = 16 Wn = 0.1198 0.4005 Specify the filter in terms of second-order sections and plot the frequency response.[z,p,k] = butter(n,Wn); sos = zp2sos(z,p,k); freqz(sos,128,1000) title(sprintf('n = %d Butterworth Bandpass Filter',n))